# How do you solve e^ { - 4x } + 8= 35?

May 18, 2017

You have to use logarithms.

#### Explanation:

${e}^{- 4 x} + 8 = 35$

${e}^{- 4 x} = 27$

$\ln 27 = - 4 x$

$\frac{\ln 27}{- 4} = x$

$\text{*} \ln$ is basically ${\log}_{e}$

$x$ is approximately $- 0.8240$.