Question

How do you solve `e^ { 6x - 7} - 5= 28,602`?

Answer 1

`x=( ln(28607)+7)/6`

Explanation:

`e^ { 6x - 7} - 5= 28,602`

`e^ { 6x - 7} = 28,607`

`ln28607=6x-7`

`x=( ln(28607)+7)/6`