How do you solve #e^ { 8v } + 3= 80#?

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Answer 1 · 2017-05-31T16:49:09

#4.34#

#e^(8v)+3 =80#

#e^(8v) = 80-3 = 77#

if #e^x=y#, then #x = log_e y = ln y#

here, #x = log_e 77 = ln 77#

on a calculator, this is

#4.3438054218536838...#, or #4.34# to #3# significant figures.

on a graph, this is:

enter image source here

[the point of intersection between the lines #x=77# and #y = ln x#. the #y-#coordinate has been rounded to #4.344, 3 d.p.#]