# How do you solve e^(k+7)=26?

Sep 6, 2016

Take the natural log of both sides.

#### Explanation:

Take the natural log of both sides.
$\ln {e}^{k + 7} = \ln 26$

Using the property of logs that allows exponents to become coefficients...
$\left(k + 7\right) \ln e = \ln 26$

The natural log of e is 1, so..
$k + 7 = \ln 26$

Subtract 7 from both sides.
$k = \ln 26 - 7$

Using a calculator,
$k = - 3.742$