How do you solve #e^lnx=12#?

1 Answer
May 8, 2016

Answer:

#x=12#

Explanation:

#color(red)(ln(x))# means #color(red)(" the value "k" you need as an exponent of e for " e^k" to be equal to x")#

Therefore
#color(white)("XXX")color(blue)(e)^color(red)(ln(x))#
means
#color(white)("XXX")color(blue)(e)# raised to the exponent of #color(red)(" the value "k" you need as an exponent of e for " e^k" to be equal to x")#

While this is a bit of a mind twister, if you think it though, what this means is that
#color(white)("XXX")e^(ln(x))=x#