How do you solve for #a# is this equation #6(1-2a) + 9a < -9 # ?

1 Answer
Apr 21, 2018

#color(red)(a > 5#

Explanation:

#" "#
Given inequality : #color(blue)(6(1-2a) + 9a < -9 #

Use Distributive Property: #color(red)(a(b+-c)=ab +-ac#

#rArr 6-12a + 9a < -9#

Simplify by adding similar terms

#rArr 6-3a <-9#

Subtract #color(red)(6# from both sides of the inequality

#rArr 6-3a - color(red)(6) <-9- color(red)(6#

#rArr cancel 6-3a - color(red)(cancel 6) <-9- color(red)(6#

#rArr -3a <-15#

Multiply both sides of the inequality by #color(red)((-1)#

You must remember to reverse the inequality symbol.

If you divide or multiply by a negative value to simplify an equality, you must reverse the inequality symbol.

#rArr -3a * color(red)((-1)) <-15*color(red)((-1)#

#rArr 3a>15#

Divide both sides of the inequality by #color(red)(3#

#rArr (3a)/color(red)(3)>15/color(red)(3#

#rArr (cancel 3a)/color(red)(cancel 3)>cancel 15^color(red)(5)/color(red)(cancel 3#

Hence,

#color(blue)(a>5# is the final solution.

You can graph this solution as shown below:

enter image source here

The dotted line indicates that #color(red)(a=5# is NOT a part of the final solution.

Hope it helps.