How do you solve for c? 5(c+7) ≤ 15(c-3)

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Answer 1 · 2017-12-11T22:37:35

#c >= 8#

expand brackets:
#5(c+7) <= 15(c-3)#

#5c+35 <= 15c-45#

subtract #5c#

#35 <= 10c-45#

#10c-45>=35#

add #45:#

#10c >= 80#

divide by #10:#

#c >= 8#