How do you solve for h in #12h=4(2h-5)#? Algebra Properties of Real Numbers When to Use the Distributive Property 1 Answer Mia Nov 20, 2016 #h=-5# Explanation: #" "# #12h = 4(2h - 5)# #" "# #rArr12h = 8h - 20# #" "# #rArr12h - 8h =-20# #" "# #rArr4h = -20# #" "# #rArr h=-20/4# #" "# #rArrh = -5# Answer link Related questions How do you simplify #(9-6y)/3#? How do you simplify #\frac{10x+8y-1}{2# using the distributive property? How do you use the distributive property to simplify #- \frac{6z - 2}{3}#? How do you simplify #6 + (x - 5) + 7#? How do you use the distributive property to simplify #(r + 3)(-5)#? What is the student error if a student rewrote #4(9x + 10)# as #36x + 10# ? How do you use the distributive property to calculate #6(19.99)# in your head? When do you use the Distributive Property? How do you use the distributive property to multiply #6(3r+4s)#? How do you use the distributive property to simplify #79(101)#? See all questions in When to Use the Distributive Property Impact of this question 2146 views around the world You can reuse this answer Creative Commons License