How do you solve for #log_x (1/64) = -3#? Precalculus Properties of Logarithmic Functions Logarithm-- Inverse of an Exponential Function 1 Answer mason m Nov 21, 2015 #x=4# Explanation: #log_x(1/64)=-3# #x^(log_x(1/64))=x^-3# #1/64=x^-3# #(1/64)^(-1/3)=(x^-3)^(-1/3)# #(64)^(1/3)=x# #4=x# Answer link Related questions What is a logarithm? What are common mistakes students make with logarithms? How can a logarithmic equation be solved by graphing? How can I calculate a logarithm without a calculator? How can logarithms be used to solve exponential equations? How do logarithmic functions work? What is the logarithm of a negative number? What is the logarithm of zero? How do I find the logarithm #log_(1/4) 1/64#? How do I find the logarithm #log_(2/3)(8/27)#? See all questions in Logarithm-- Inverse of an Exponential Function Impact of this question 4716 views around the world You can reuse this answer Creative Commons License