How do you solve for #r^2#: #S = 4\pir^2h#?

1 Answer
smendyka
Sep 25, 2017

See a solution process below:

Explanation:

Divide each side of the equation by #color(red)(4)color(blue)(pi)color(green)(h)# to solve for #r^2# while keeping the equation balanced:

#S/(color(red)(4)color(blue)(pi)color(green)(h)) = (4pir^2h)/(color(red)(4)color(blue)(pi)color(green)(h))#

#S/(4pih) = (color(red)(cancel(color(black)(4)))color(blue)(cancel(color(black)(pi)))r^2color(green)(cancel(color(black)(h))))/(cancel(color(red)(4))cancel(color(blue)(pi))cancel(color(green)(h)))#

#S/(4pih) = r^2#

#r^2 = S/(4pih)#

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