How do you solve for R in #3214 = (1 + R)^4#?

Question

1973 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-29T13:38:27

#R~=6.52942# or #R~= -8.52942# (Assuming #R in RR#)

#(1+R)^4 = 3214#

#(1+R) = root4(3214) #

#1+R ~=+-7.52942# (Assuming #R in RR#)

Hence: #R~=6.52942# or #R~= -8.52942#

Answer 2 · 2016-09-04T14:08:19

#R = pm root(4)(3214) - 1#

We have: #3214 = (1 + R)^(4)#

Take the fourth root of both sides:

#=> (1 + R) = pm root(4)(3214)#

#=> R = pm root(4)(3214) - 1#