How do you solve for #r# in the equation #p=4r+3t#?

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Answer 1 · 2018-03-24T20:22:10

#r=(p-3t)/4#

Isolate r (no coefficients)

#p=4r+3t#

#p-3t=4r#

#r=(p-3t)/4#

Answer 2 · 2018-03-24T20:22:51

#r=p/4-(3t)/4#

#p=4r+3t#
#4r+3t=p#
#4r=p-3t#
#r=p/4-(3t)/4#

Hope this helps!