How do you solve for the angles of this triangle with the following equations?
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The steps I used:
1. sqrt(10^2+16^2+2*16*10*cos(110))
- Cos(110)/c = Cos(A)/16
.
The steps I used:
1.
- Cos(110)/c = Cos(A)/16
1 Answer
Apr 23, 2018
Explanation:
"using the formulae sine/cosine rules"
"we require to find side c"
"using the "color(blue)"cosine rule"
•color(white)(x)c^2=a^2+b^2-(2abcos110)
rArrc=sqrt(16^2+10^2-(2xx16xx10cos110)
color(white)(rArrc)=sqrt(256+100+109.445..)
color(white)(rArrc)~~21.57
"calculate "angleA" using the "color(blue)"sine rule"
•color(white)(x)a/(sinA)=b/(sinB)=c/(sinC)
rArr16/(sinA)=21.57/(sin110)
rArrsinA=(16xxsin110)/21.57
rArrangleA=sin^-1((16xxsin110)/21.57)~~44.2^@
"Find "angleB" using angle sum of triangle"
rArrangleB=180-(110+44.2)~~25.8^@