How do you solve for the angles of this triangle with the following equations?

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The steps I used:
1. sqrt(10^2+16^2+2*16*10*cos(110))

  1. Cos(110)/c = Cos(A)/16

1 Answer
Apr 23, 2018

"see explanation"

Explanation:

"using the formulae sine/cosine rules"

"we require to find side c"

"using the "color(blue)"cosine rule"

•color(white)(x)c^2=a^2+b^2-(2abcos110)

rArrc=sqrt(16^2+10^2-(2xx16xx10cos110)

color(white)(rArrc)=sqrt(256+100+109.445..)

color(white)(rArrc)~~21.57

"calculate "angleA" using the "color(blue)"sine rule"

•color(white)(x)a/(sinA)=b/(sinB)=c/(sinC)

rArr16/(sinA)=21.57/(sin110)

rArrsinA=(16xxsin110)/21.57

rArrangleA=sin^-1((16xxsin110)/21.57)~~44.2^@

"Find "angleB" using angle sum of triangle"

rArrangleB=180-(110+44.2)~~25.8^@