How do you solve for the power of $x$ ? For example, $2^x = 423$ . How do you get $x$ ?

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Answer 1 · 2014-10-02T00:23:47

$2^x=423$

Take the natural log of both sides

$ln (2^x)= ln (423)$

Use one of properties of logs to move the exponent down as a factor

$x*ln (2)=ln(423)$

Use Algebra to solve for $x$ by dividing by $ln(x)$

$(x*ln (2))/(ln(2))=ln(423)/(ln(2))$

Use a calculator to resolve the division

$x=ln(423)/(ln(2))=8.724513853$

How do you solve for the power of xx? For example, 2^x = 4232^x = 423. How do you get xx?