How do you solve for $x$ in $2x+6=10$ ?

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Answer 1 · 2018-06-30T17:27:26

$x=2$

$"subtract 6 from both sides of the equation"$

$2x=10-6=4$

$"divide both sides by 2"$

$(cancel(2) x)/cancel(2)=4/2rArrx=2$

How do you solve for xx in 2x+6=102x+6=10?