# How do you solve for x in #48/125=(3x)/25#?

##### 1 Answer

Feb 11, 2017

#### Explanation:

One way is to express the fraction on the right side with the equivalent denominator to the fraction on the left side.

#rArr(3x)/25xx5/5=(15x)/125# We now have

#48/125=(15x)/125# Since the fractions are equal and have the same denominator, then their numerators must be equal.

#rArr15x=48#

#rArrx=48/15=16/5#