How do you solve for x in #48/125=(3x)/25#?

1 Answer
Feb 11, 2017

Answer:

#x=16/5#

Explanation:

One way is to express the fraction on the right side with the equivalent denominator to the fraction on the left side.

#rArr(3x)/25xx5/5=(15x)/125#

We now have #48/125=(15x)/125#

Since the fractions are equal and have the same denominator, then their numerators must be equal.

#rArr15x=48#

#rArrx=48/15=16/5#