How do you solve for x in $6 = (\frac{4}{7}) x$ $6 = (4/7)x$ ?

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Answer 1 · 2018-04-22T21:49:13

$x = \frac{42}{4}$ $x = 42/4$ or $10.5$ $10.5$

$6 = \frac{4}{7} x$ $6 = 4/7 x$

$\frac{4}{7} \cdot \frac{7}{4} = \frac{28}{28} = 1$ $4/7 * 7/4 = 28/28 = 1$

$\frac{4}{7} x \cdot \frac{7}{4} = \frac{28 x}{28} = 1$ $4/7x * 7/4 = (28x)/28 = 1$

if $\frac{4}{7} x = 6$ $4/7x = 6$ , then $x = \frac{7}{4} \cdot 6$ $x = 7/4 * 6$

$\frac{7}{4} \cdot 6 = \frac{7 \cdot 6}{4}$ $7/4 * 6 = (7 * 6)/4$

$= \frac{42}{4}$ $= 42/4$

in decimal form, this is $10.5$ $10.5$ .

How do you solve for x in 6 = (4/7)x6=(47)x6 = (4/7)x?