How do you solve for #x# in #qx - m - 5= 3w#?

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Answer 1 · 2018-01-27T23:58:12

See a solution process below:

First, add #color(red)(m)# and #color(blue)(5)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#qx - m + color(red)(m) - 5 + color(blue)(5) = 3w + color(red)(m) + color(blue)(5)#

#qx - 0 - 0 = 3w + m + 5#

#qx = 3w + m + 5#

Now, divide each side of the equation by #color(red)(q)# to solve for #x# while keeping the equation balanced:

#(qx)/color(red)(q) = (3w + m + 5)/color(red)(q)#

#(color(red)(cancel(color(black)(q)))x)/cancel(color(red)(q)) = (3w + m + 5)/q#

#x = (3w + m + 5)/q#

Or

#x = (3w)/q + m/q + 5/q#