How do you solve for x in the following equation: #(4-x)/5 +5 = 5/2#?

1 Answer
Jul 28, 2017

See a solution process below:

Explanation:

Step 1) Subtract #color(red)(5)# from each side of the equation to isolate the fraction while keeping the equation balanced:

#(4 - x)/5 + 5 - color(red)(5) = 5/2 - color(red)(5)#

#(4 - x)/5 + 0 = 5/2 - (2/2 xx color(red)(5))#

#(4 - x)/5 = 5/2 - 10/2#

#(4 - x)/5 = -5/2#

Step 2) Multiply each side of the equation by #color(red)(5)# to eliminate the fraction on the left side of the equation while keeping the equation balanced:

#color(red)(5) xx (4 - x)/5 = color(red)(5) xx -5/2#

#cancel(color(red)(5)) xx (4 - x)/color(red)(cancel(color(black)(5))) = -25/2#

#4 - x = -25/2#

Step 3) Subtract #color(red)(4)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#-color(red)(4) + 4 - x = -color(red)(4) - 25/2#

#0 - x = (2/2 xx -color(red)(4)) - 25/2#

#-x = -8/2 - 25/2#

#-x = -33/2#

Step 4) Multiply each side of the equation by #color(red)(-1)# to solve for #x# while keeping the equation balanced:

#color(red)(-1) xx -x = color(red)(-1) xx -33/2#

#x = 33/2#