How do you solve for # x# in this equation #2x+4-10x = 20#?

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Answer 1 · 2017-06-09T12:19:43

See a solution process below:

First, group and combine like terms on the left side of the equation:

#2x + 4 - 10x = 20#

#2x - 10x + 4 = 20#

#(2 - 10)x + 4 = 20#

#-8x + 4 = 20#

Next, subtract #color(red)(4)# from each side of the equation to isolate the #x# term:

#-8x + 4 - color(red)(4) = 20 - color(red)(4)#

#-8x + 0 = 16#

#-8x = 16#

Now, divide each side of the equation by #color(red)(-8)# to solve for #x# while keeping the equation balanced:

#(-8x)/color(red)(-8) = 16/color(red)(-8)#

#(color(red)(cancel(color(black)(-8)))x)/cancel(color(red)(-8)) = -2#

#x = -2#