How do you solve for $x$ in this equation $2x+4-10x = 20$ ?

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Answer 1 · 2017-06-09T12:19:43

See a solution process below:

First, group and combine like terms on the left side of the equation:

$2x + 4 - 10x = 20$

$2x - 10x + 4 = 20$

$(2 - 10)x + 4 = 20$

$-8x + 4 = 20$

Next, subtract $color(red)(4)$ from each side of the equation to isolate the $x$ term:

$-8x + 4 - color(red)(4) = 20 - color(red)(4)$

$-8x + 0 = 16$

$-8x = 16$

Now, divide each side of the equation by $color(red)(-8)$ to solve for $x$ while keeping the equation balanced:

$(-8x)/color(red)(-8) = 16/color(red)(-8)$

$(color(red)(cancel(color(black)(-8)))x)/cancel(color(red)(-8)) = -2$

$x = -2$

How do you solve for x x in this equation 2x+4-10x = 202x+4-10x = 20?