Question

How do you solve for x?: `log_2(2^(x+3))=15`?

Answer 1

`x=12`

Explanation:

`log_2(2^(x+3))=15=>` if `log_a(x)=yhArrx=a^y` , so:

`2^(x+3)=2^15=>`when the same bases to different exponents are

equal then the exponents must be equal, then:

`x+3=15=>` subtract 3 from both sides:

`x=12`