Question

How do you solve `\frac { 1} { 12} ( 48+ 24b) = 2( 17- 4b )`?

Answer 1

`1/12(48+24b)=2(17−4b)`

`(48/12+(24b)/12)=2*17−2*4b`

`4+2b=34−8b`

`2b+8b=34-4`

`10b=30`

`b=3`

-Sahar.