How do you solve #\frac { 1} { 16} \cdot 4^ { x } = 20#?

1 Answer
Jan 7, 2018

#x~~4.161#

Explanation:

If #1/6 * 4^x=20#
then
#color(white)("XXX")4^x=16 * 20=4^3 * 5#

#color(white)("XXX")4^(x-3)=5#

#color(white)("XXX")x-3=log_4 5 =~~1.16096407# (using calculator)

#color(white)("XXX")x=4.16096407#