How do you solve #\frac { 1 } { 2 } ( - 4 + 6 x ) = \frac { 1 } { 3 } x + \frac { 2 } { 3 } ( x + 9 )#?

1 Answer
Apr 1, 2018

x=4

Explanation:

First, use distributive property on the #(1/2)(-4+6x)# and #(2/3)(x+9)#.

#(1/2)(-4+6x) = (1/2)*-4+(1/2)*6x = -2+3x#
#(2/3)(x+9) = (2/3)*x+(2/3)*9 = 2/3x+6#

The equation is now #-2+3x=1/3x+2/3x+6#.

Combine like terms and make it "prettier".

#3x-2=x+6#.

Now we've broken it down into something much more simple!

Subtract #6# from both sides to get
#3x-2-6=x+6-6 => 3x-8=x#

Subtract #x# from both sides to get
#3x-x-8 = x-x => 2x-8=0#

Add #8# to both sides to get
#2x-8+8=0+8 => 2x=8#

Final step: Divide #2# from both sides to get
#2x/2=8/2 => x=4#

Therefore, #x=4#.

Yay!