How do you solve #-\frac{1}{2} n + n = \frac{1}{6}#?

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Answer 1 · 2016-09-29T22:39:13

#n = (1) / (3)#

We have: #- (1) / (2) n + n = (1) / (6)#

First, let's combine the terms containing #n#:

#=> (1) / (2) n = (1) / (6)#

Then, let's cross-multiply:

#=> 6 n = 2#

Finally, to solve for #n#, let's divide both sides of the equation by #6#:

#=> n = (2) / (6)#

#=> n = (1) / (3)#

Therefore, the solution to the equation is #n = (1) / (3)#.