How do you solve #-\frac { 1} { 2} + y = - \frac { 3} { 7}#?
1 Answer
Dec 10, 2016
Explanation:
To 'eliminate' the fractions on both sides of the equation, multiply ALL terms by the
#color(blue)"lowest common multiple"# (LCM) of the denominators 2 and 7. This is 14
#(cancel(14)^7xx-1/cancel(2)^1)+(14xxy)=(cancel(14)^2xx-3/cancel(7)^1)#
#rArr(7xx-1)+14y=(2xx-3)#
#rArr-7+14y=-6larr" no fractions"# leave 14y on left side of equation and collect numeric values on the right side.
add 7 to both sides of the equation.
#cancel(-7)cancel(+7)+14y=-6+7#
#rArr14y=1# To solve for y, divide both sides by 14
#(cancel(14) y)/cancel(14)=1/14#
#rArry=1/14" is the solution"#
#color(blue)"Check solution"#
#"left side " = -1/2+1/14#
#=-7/14+1/14=-6/14=-3/7=" right side " ✔︎#