How do you solve #\frac { 1} { 2y + 10} + 4= - \frac { 8} { y + 5}#?

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Answer 1 · 2017-06-05T01:35:03

#y = -57/8 = -7.125#

Move all the terms with #y# to the right side:

#1/(2y+10) + 4 = -8/(y+5)#

#4 = -8/(y+5) - 1/(2y+10)#

Note that #2y+10 = 2(y+5)#

#4 = -8/(y+5) - 1/(2(y+5))#

Multiply both sides by #y+5# and solve normally.

#4(y+5) = -8 - 1/2#

#4y + 20 = -17/2#

#4y = -57/2#

#y = -57/8 = -7.125#

Final Answer