How do you solve #\frac { 1} { 3} \log _ { 2} x - 3= 0#?

1 Answer
Sep 8, 2017

#x=color(red)(512)#

Explanation:

If #1/3 log_2x-3=0#
then
#color(white)("XXX")1/3log_2x=3#

#color(white)("XXX")log_2x=9#

Remembering that #log_ba=c# means that #b^c=a#

we have
#color(white)("XXX")2^9=x#

and since #2^9=512#
#color(white)("XXX")x=512#