Question

How do you solve `\frac { 1} { 3} \log _ { 2} x - 3= 0`?

Answer 1

`x=color(red)(512)`

Explanation:

If `1/3 log_2x-3=0`
then
`color(white)("XXX")1/3log_2x=3`

`color(white)("XXX")log_2x=9`

Remembering that `log_ba=c` means that `b^c=a`

we have
`color(white)("XXX")2^9=x`

and since `2^9=512`
`color(white)("XXX")x=512`