How do you solve #\frac { 1 } { 4 } ( 4 r - 8 ) = r - 2#?

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Answer 1 · 2018-04-24T12:20:50

There are an infinite number of solutions.

#=> 1/4(4r - 8) = r - 2#

Multiply both sides by #4#

#=>1/cancel(4) (4r - 8) × cancel(4) = 4(r - 2)#

#=> 4r - 8 = 4r - 8#

#=> 4r - 4r = 8 - 8#

#=> 0 = 0#

#r# is any number.