How do you solve #\frac { 1} { 4} ( 8x + 16) = - 10#?

1 Answer
Jul 23, 2017

See a solution process below:

Explanation:

Step 1) Multiply each side of the equation by #color(red)(4)# to eliminate the parenthesis while keeping the equation balanced:

#color(red)(4) xx 1/4(8x + 16) = color(red)(4) xxx -10#

#cancel(color(red)(4)) xx 1/color(red)(cancel(color(black)(4)))(8x + 16) = -40#

#8x + 16 = -40#

Step 2) Subtract #color(red)(16)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#8x + 16 - color(red)(16) = -40 - color(red)(16)#

#8x + 0 = -56#

#8x = -56#

Step 3) Divide each side of the equation by #color(red)(8)# to solve for #x# while keeping the equation balanced:

#(8x)/color(red)(8) = -56/color(red)(8)#

#(color(red)(cancel(color(black)(8)))x)/cancel(color(red)(8)) = -7#

#x = -7#