How do you solve #\frac { 1} { 57} b = \frac { 21090} { 285}#?

1 Answer
Jan 31, 2018

See a solution process below:

Explanation:

Multiply each side of the equation by #color(red)(57)# to solve for #b# while keeping the equation balanced:

#color(red)(57) xx 1/57b = color(red)(57) xx 21090/285#

#cancel(color(red)(57)) xx 1/color(red)(cancel(color(black)(57)))b = cancel(color(red)(57)) xx 21090/(color(red)(cancel(color(black)(285)))5)#

#1b = 21090/5#

#b = 4218#