Question

How do you solve `\frac { 1} { x + 1} + \frac { 2} { x + 3} \leq 0`?

Answer 1

`x in (-infty, -3) cup [-5/3 , -1)`

Explanation:

`frac{x + 3 + 2x + 2}{(x + 1)(x + 3)} <= 0`

`(3x + 5)(x + 1)(x + 3) < 0 or x = -5/3`

Signals: `-` `0` `+` `0` `-` `0` `+`

`x < -3 or -5/3 <= x < -1`