How do you solve #\frac { 2} { 3} ( - 7) + \frac { 2} { 3} ( - 5)#?

1 Answer
Oct 23, 2016

#-8#

Explanation:

The first step is to evaluate the multiplications on either side of the + sign.

#2/3xx(-7)/1=(2xx-7)/(3xx1)=(-14)/3#

and #2/3xx(-5)/1=(2xx-5)/(3xx1)=(-10)/3#

So now we have #(-14)/3+(-10)/3#

Since the fractions have common denominators , we can add the numerators directly.

#rArr(-14+(-10))/3=(-14-10)/3=(-24)/3=-8#

Alternatively, if you are familiar with #color(blue)"common factor"# then there is a common factor of #2/3# in both terms.

#rArr2/3(-7+(-5))=2/3(-7-5)=2/3(-12)#

Evaluating gives.

#2/3xx(-12)/1=(-24)/3=-8#