How do you solve #\frac { 2} { 3} ( - 7) + \frac { 2} { 3} ( - 5)#?
1 Answer
Oct 23, 2016
Explanation:
The first step is to evaluate the multiplications on either side of the + sign.
#2/3xx(-7)/1=(2xx-7)/(3xx1)=(-14)/3# and
#2/3xx(-5)/1=(2xx-5)/(3xx1)=(-10)/3# So now we have
#(-14)/3+(-10)/3# Since the fractions have common denominators , we can add the numerators directly.
#rArr(-14+(-10))/3=(-14-10)/3=(-24)/3=-8# Alternatively, if you are familiar with
#color(blue)"common factor"# then there is a common factor of#2/3# in both terms.
#rArr2/3(-7+(-5))=2/3(-7-5)=2/3(-12)# Evaluating gives.
#2/3xx(-12)/1=(-24)/3=-8#