How do you solve #-\frac{2}{3} = \frac{3}{4} n - \frac{1}{3}#?

1 Answer
Jim G.
Oct 6, 2016

#n=-4/9#

Explanation:

We can rewrite the equation as follows.

#3/4n-1/3=-2/3larr" reversing the equation"#

add #1/3# to both sides.

#3/4ncancel(-1/3)cancel(+1/3)=-2/3+1/3#

#rArr3/4n=-1/3rArr(3n)/4=-1/3#

Multiplying both sides by 12 (LCM of 3 and 4 ) will eliminate the fractions.

#cancel(12)^3xx(3n)/cancel(4)^1=cancel(12)^4xx-1/cancel(3)^1#

#rArr9n=-4#

To solve for n, divide both sides by 9.

#(cancel(9) n)/cancel(9)=-4/9#

#rArrn=-4/9" is the solution"#

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