How do you solve #-\frac{2}{3} y = 22#?

1 Answer
EZ as pi
Sep 24, 2016

#y = -33#

Explanation:

#-2/3 y = 22#

In solving this equation we need to isolate #y#.

This involves removing :
#rarr#the negative sign #" "rarr xx #by a negative
#rarr#a multiplication by 2 #" "rarr div 2#
#rarr# a division by 3 #" "rarr xx 3#

#color(red)(-3/2) xx -2/3 y = color(red)(-3/2) xx 22#

Everything on the left cancels, leaving just #y#
Calculate the result on the right side.

#y = -33#

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