How do you solve #-\frac { 2} { 3} y + 8= 26#?

2 Answers
Apr 22, 2017

#y=-27#

Explanation:

Solve:

#-2/3y+8=26#

Rewrite #-2/3y# as #-(2y)/3#

#-(2y)/3+8=26#

Subtract #8# from both sides.

#-(2y)/3+color(red)cancel(color(black)(8))-color(red)cancel(color(black)(8))=26-8#

Simplify.

#-(2y)/3=18#

Multiply both sides by #3#.

#-(2y)/color(red)cancel(color(black)(3))xxcolor(red)cancel(color(black)(3))=18xx3#

Simplify.

#-2y=54#

Divide both sides by #-2#.

#(color(red)cancel(color(black)(-2))y)/(color(red)cancel(color(black)(-2)))=54/(-2)#

Simplify. (A negative divided by a negative makes a positive, and a positive divided by a negative makes a negative.)

#y=-27#

Check.

#-2/3xxcolor(green)(-27)+8=26#

Apr 22, 2017

See the entire solution process below:

Explanation:

First, subtract #color(red)(8)# from each side of the equation to isolate the #y# term while keeping the equation balanced:

#-2/3y + 8 - color(red)(8) = 26 - color(red)(8)#

#-2/3y + 0 = 18#

#-2/3y = 18#

Now, multiply each side of the equation by #color(red)(3)/color(blue)(-2)# to solve for #y# while keeping the equation balanced:

#color(red)(3)/color(blue)(-2) * (-2)/3y = color(red)(3)/color(blue)(-2) * 18#

#cancel(color(red)(3))/cancel(color(blue)(-2)) * color(blue)(cancel(color(black)(-2)))/color(red)(cancel(color(black)(3)))y = 54/color(blue)(-2)#

#y = -27#