How do you solve #-\frac { 2} { 3} z = - 6#?

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Answer 1 · 2017-02-22T12:26:40

#z# = 9

#-2/3z = -6#

Reverse

#z = -\frac{6}{-\frac{2}{3}}#

#--\frac{6}{-\frac{2}{3}} = \frac{6}{-\frac{2}{3}}#

#"Apply the fraction rule"\quad \frac{a}{-b}=-\frac{a}{b}#

#\frac{6}{-\frac{2}{3}} = -\frac{6}{\frac{2}{3}}#

#\"Apply the fraction rule":\quad \frac{a}{\frac{b}{c}}=\frac{a\c}{b}#

#-\frac{6}{\frac{2}{3}}# = #-"3 * 6"/2 = -18/2#

= #-(-18/2)#

= #-(-9)#

=# +9#