How do you solve #\frac { 2} { 3x } - \frac { 1} { 2x } = \frac { 3} { 4}#?

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Answer 1 · 2018-01-16T19:25:31

#x = 2/9#

#2/(3x) - 1/(2x) = 3/4#

Let's combine these two fractions. TO do that, they need to have a common denominator

#(2x)/(2x) xx 2/(3x) - 1/(2x) xx (3x)/(3x) = 3/4#

#(4x)/(6x^2) - (3x)/(6x^2) = 3/4#

#x/(6x^2) = 3/4#

#1/(6x) = 3/4#

#6x xx 1/(6x) = 3/4 xx 6x#

#1 = (18x)/4#

#4 xx 1 = (18x)/4 xx 4#

#4 = 18x#

#x = 4/18# or #2/9#