First, multiply each side of the equation by #color(red)(4)# to eliminate the fractions while keeping the equation balanced:
#color(red)(40)(2/5m - 1/5) = color(red)(40) xx 9/40#
#(color(red)(40) xx 2/5m) - (color(red)(40) xx 1/5) = cancel(color(red)(40)) xx 9/color(red)(cancel(color(black)(40)))#
#(cancel(color(red)(40))8 xx 2/color(red)(cancel(color(black)(5)))m) - (cancel(color(red)(40))8 xx 1/color(red)(cancel(color(black)(5)))) = cancel(color(red)(40)) xx 9/color(red)(cancel(color(black)(40)))#
#16m - 8 = 9#
Next, subtract #color(red)(8)# from each side of the equation to isolate the #m# term while keeping the equation balanced:
#16m - 8 + color(red)(8) = 9 + color(red)(8)#
#16m - 0 = 17#
#16m = 17#
Now, divide each side of the equation by #color(red)(16)# to solve for #m# while keeping the equation balanced:
#(16m)/color(red)(16) = 17/color(red)(16)#
#(color(red)(cancel(color(black)(16)))m)/cancel(color(red)(16)) = 17/16#
#m = 17/16#