How do you solve #\frac { 2- 5x } { 4} > 3#?

1 Answer
Aug 13, 2017

See a solution process below:

Explanation:

First, multiply each side of the inequality by #color(red)(4)# to eliminate the fraction while keeping the inequality balanced:

#color(red)(4) xx (2 - 5x)/4 > color(red)(4) xx 3#

#cancel(color(red)(4)) xx (2 - 5x)/color(red)(cancel(color(black)(4))) > 12#

#2 - 5x > 12#

Next, subtract #color(red)(2)# from each side of the inequality to isolate the #x# term while keeping the inequality balanced:

#-color(red)(2) + 2 - 5x > -color(red)(2) + 12#

#0 - 5x > 10#

#-5x > 10#

Now, divide each side of the inequality by #color(blue)(-5)# to solve for #x# while keeping the inequality balanced. However, because we are multiplying or dividing an inequality by a negative number we need to reverse the inequality operator:

#(-5x)/color(blue)(-5) color(red)(<) 10/color(blue)(-5)#

#(color(blue)(cancel(color(black)(-5)))x)/cancel(color(blue)(-5)) color(red)(<) -2#

#x < -2#