How do you solve #\frac { 2} { 7} q + 3= 9#?

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Answer 1 · 2017-07-23T22:01:02

See a solution process below:

Step 1) Subtract #color(red)(3)# from each side of the equation to isolate the #q# term while keeping the equation balanced:

#2/7q + 3 - color(red)(3) = 9 - color(red)(3)#

#2/7q + 0 = 6#

#2/7q = 6#

Step 2) Multiply each side of the equation by #color(red)(7)/color(blue)(2)# to solve for #q# while keeping the equation balanced:

#color(red)(7)/color(blue)(2) * 2/7q = color(red)(7)/color(blue)(2) * 6#

#cancel(color(red)(7))/cancel(color(blue)(2)) * color(blue)(cancel(color(black)(2)))/color(red)(cancel(color(black)(7)))q = 42/color(blue)(2)#

#q = 21#