How do you solve #\frac { 2} { x + 2} - \frac { 1} { x - 2} = \frac { 2x } { x ^ { 2} - 4}#?

1 Answer
Aug 23, 2017

#x=-6#

Explanation:

Given:

#2/(x+2)-1/(x-2) = (2x)/(x^2-4)#

Note that:

#(x-2)(x+2) = x^2-4#

So multiplying the whole equation by #x^2-4# we get:

#2(x-2)-1(x+2) = 2x#

That is:

#x-6 = 2x#

Subtracting #x# from both sides, we find:

#x = -6#

This is a valid solution of the original equation, since it is not a zero of #x^2-4#.