How do you solve #\frac { 2} { x + 2} - \frac { 1} { x - 2} = \frac { 2x } { x ^ { 2} - 4}#?
1 Answer
Aug 23, 2017
Explanation:
Given:
#2/(x+2)-1/(x-2) = (2x)/(x^2-4)#
Note that:
#(x-2)(x+2) = x^2-4#
So multiplying the whole equation by
#2(x-2)-1(x+2) = 2x#
That is:
#x-6 = 2x#
Subtracting
#x = -6#
This is a valid solution of the original equation, since it is not a zero of