How do you solve #\frac { 2( y - 2) } { 4} + 7= 14#?

1 Answer
Mar 25, 2017

Isolate #y# by performing opposite operations. As a result, #y=16#.

Explanation:

Solving the equation indicates isolating the variable, in this case, it is #y#. Given what the equation equals to, we can perform opposite operations to work backwards and ultimately isolate #y#.

#(2(y−2))/4+7=14#

First, let's remove the constant, #7#, by subtracting it from #14#.

#(2(y−2))/4=7#

Now, let's remove the #4#, by multiplying the #7# that we got from the previous step.

#2(y−2)=28#

Now, let's remove the coefficient, #2#, that is outside the bracket. We can do this by dividing #28# by #2#.

#(y−2)=14#

Lastly, we can now remove the remaining #2#, by adding it to #14#.

#y=16#

Therefore, #y=16#.

We can double check this by subbing in #y=16# into the original equation.

#(2(y−2))/4+7=14#

#(2(16−2))/4+7=14#

#(2(14))/4+7=14#

#28/4+7=14#

#7+7=14#

#14=14#

After subbing in #y=16#, we can conclude that #y# does in fact, equal #16#.

Hope this helps :)