How do you solve #\frac { 21} { 56} = 3/x#?

1 Answer
Nov 22, 2017

See a solution process below:

Explanation:

First, we can reduce the fraction on the left side of the equation:

#(7 * 3)/(7 * 8) = 3/x#

#(color(red)(cancel(color(black)(7))) * 3)/(color(red)(cancel(color(black)(7))) * 8) = 3/x#

#3/8 = 3/x#

Because both sides of the equation are pure fractions we can flip the fractions to rewrite the equation as:

#8/3 = x/3#

Now, multiply each side of the equation by #color(red)(3)# to solve for #x# while keeping the equation balanced:

#color(red)(3) xx 8/3 = color(red)(3) xx x/3#

#cancel(color(red)(3)) xx 8/color(red)(cancel(color(black)(3))) = cancel(color(red)(3)) xx x/color(red)(cancel(color(black)(3)))#

#8 = x#

#x = 8#

After reducing the fractions, we also observe the numerator of both fractions are the same and therefore the denominators must be the same if they are equal:

#color(red)(3)/8 = color(red)(3)/x#

Therefore:

#8 = x# or #x = 8#