How do you solve #\frac { 2n } { 3} + \frac { 5n } { 2} = \frac { 19} { 2}#?

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Answer 1 · 2017-07-01T04:59:51

#n=3#

#(2n)/3+(5n)/2=19/2#

Multiply all terms by #6# (the LCM of #3# and #2#).

#6xx(2n)/3+6xx(5n)/2=6xx19/2#

#2cancel6xx(2n)/(1cancel3)+3cancel6xx(5n)/(icancel2)=3cancel6xx19/(1cancel2)#

#2xx2n+3xx5n=3xx19#

#4n+15n=3xx19#

#19n=3xx19#

Divide both sides by #19#.

#(19n)/19=(3xx19)/19#

#(1cancel19n)/(1cancel19)=(3xx1cancel19)/(1cancel19)#

#n=3#