How do you solve #\frac { - ( 2x + 4) } { 8} = 3#?

2 Answers
Nov 4, 2016

Answer:

#x=-14#

Explanation:

# (-(2x + 4))/8 = 3#

# ((-(2x + 4))/8) * 8= 3 *8#

# -(2x+4) = 24#

#-2x -4 = 24#
#-2x -4 +4 = 24+4#
#-2x = 28#
#(-2x)/-2 = 28/-2#
# x= -14#

Nov 4, 2016

Answer:

#x = -14#

Explanation:

Step 1) Multiple each side of the equation by #8# to eliminate the fraction.
Step 2) Multiple the term in parenthesis by #-1# to remove the parenthesis
Step 3) Solve for #x# while keeping the equation balanced

#8((-(2x + 4))/8) = 3*8#

#-(2x + 4) = 24#

#-2x - 4 = 24#

#-2x - 4 + 4 = 24 + 4#

#-2x - 0 = 28#

#-2x = 28#

#-2(x/-2) = 28/-2#

#1x = -14#

#x = -14#