How do you solve \frac { - ( 2x + 4) } { 8} = 3?

2 Answers
Nov 4, 2016

$x = - 14$

Explanation:

$\frac{- \left(2 x + 4\right)}{8} = 3$

$\left(\frac{- \left(2 x + 4\right)}{8}\right) \cdot 8 = 3 \cdot 8$

$- \left(2 x + 4\right) = 24$

$- 2 x - 4 = 24$
$- 2 x - 4 + 4 = 24 + 4$
$- 2 x = 28$
$\frac{- 2 x}{-} 2 = \frac{28}{-} 2$
$x = - 14$

Nov 4, 2016

$x = - 14$

Explanation:

Step 1) Multiple each side of the equation by $8$ to eliminate the fraction.
Step 2) Multiple the term in parenthesis by $- 1$ to remove the parenthesis
Step 3) Solve for $x$ while keeping the equation balanced

$8 \left(\frac{- \left(2 x + 4\right)}{8}\right) = 3 \cdot 8$

$- \left(2 x + 4\right) = 24$

$- 2 x - 4 = 24$

$- 2 x - 4 + 4 = 24 + 4$

$- 2 x - 0 = 28$

$- 2 x = 28$

$- 2 \left(\frac{x}{-} 2\right) = \frac{28}{-} 2$

$1 x = - 14$

$x = - 14$