How do you solve #|\frac { 2x - 5} { 7} | = 3#?

1 Answer
Oct 15, 2016

#color(blue)(barul(|color(white)(4/3)x=13,-8color(white)(3/7)|#

Explanation:

#color(blue)(|(2x-5)/7|=3#

This is an absolute value value equation

So,we can divide the equation into two

#color(green)((2x-5)/7=3# #and# #color(purple)((2x-5)/7=-3#

Solve for both the equations

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(green)(rarr(2x-5)/7=3#

#color(green)(rarr(2x-5)=3*7#

#color(green)(rarr2x-5=21#

#color(green)(rarr2x=21+5#

#color(green)(rarr2x=26#

#color(green)(rarrx=26/2#

#rArrcolor(green)(barul(|color(white)(3/3)x=13color(white)(5/6)|#

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

#color(purple)(rarr(2x-5)/7=-3#

#color(purple)(rarr(2x-5)=-3*7#

#color(purple)(rarr2x-5=-21#

#color(purple)(rarr2x-5=-21#

#color(purple)(rarr2x=-21+5#

#color(purple)(rarr2x=-16#

#color(purple)(rarrx=-16/2#

#rArrcolor(purple)(barul(|color(white)(3/3)x=-8color(white)(3/3)|#

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

#:.color(blue)(barul(|color(white)(4/3)x=13,-8color(white)(3/7)|#