How do you solve #\frac { 2x } { 6} + 1= 4#?

1 Answer
smendyka
Nov 22, 2016

#x = 9#

Explanation:

To isolate and solve for #x#, execute the necessary mathematics to keep the equation balanced, starting with subtracting 1 from each side of the equation:

#(2x)/6 + 1 -1 = 4 - 1#

#(2x)/6 + 0 = 3#

#(2x)/6 = 3#

Next, multiply each side of the equation by #6/2# to solve for #x#:

#(6/2) (2x)/6 = (6/2)*3#

#(cancel(6)/cancel(2)) (cancel(2)x)/cancel(6) = 18/2#

#x = 18/2#

#x = 9#

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