How do you solve $\frac{3}{2} f = \frac{1}{2}$ $\frac { 3} { 2} f = \frac { 1} { 2}$ ?

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Answer 1 · 2016-11-24T03:24:54

$f = \frac{1}{3}$ $f = 1/3$

$\frac{3 f}{2} = \frac{1}{2}$ $(3f)/2=1/2$

Multiply both sides by $\frac{2}{3}$ $2/3$

$(\frac{2}{3}) \cdot \frac{3 f}{2} = (\frac{2}{3}) (\frac{1}{2})$ $(2/3)*(3f)/2=(2/3)(1/2)$

$(cancel2/cancel3)*(cancel3f)/cancel2=(cancel2/3)(1/cancel2)$

$f = 1/3$

God bless....I hope the explanation is useful.

How do you solve \frac { 3} { 2} f = \frac { 1} { 2}32f=12\frac { 3} { 2} f = \frac { 1} { 2}?