How do you solve #\frac{3}{4} ( 3x + 9) = 62#?
1 Answer
Sep 22, 2016
Explanation:
To eliminate the fraction multiply both sides of the equation by 4.
#cancel(4)^1xx3/cancel(4)^1(3x+9)=4xx62#
#rArr3(3x+9)=248# now distribute the bracket.
#9x+27=248# subtract 27 from both sides.
#9xcancel(+27)cancel(-27)=248-27#
#rArr9x=221# To solve for x divide both sides by 9.
#(cancel(9) x)/cancel(9)=221/9#
#rArrx=221/9" is the solution"#