How do you solve #\frac{3}{4} ( 3x + 9) = 62#?

1 Answer
Sep 22, 2016

#x=221/9#

Explanation:

To eliminate the fraction multiply both sides of the equation by 4.

#cancel(4)^1xx3/cancel(4)^1(3x+9)=4xx62#

#rArr3(3x+9)=248#

now distribute the bracket.

#9x+27=248#

subtract 27 from both sides.

#9xcancel(+27)cancel(-27)=248-27#

#rArr9x=221#

To solve for x divide both sides by 9.

#(cancel(9) x)/cancel(9)=221/9#

#rArrx=221/9" is the solution"#